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2x+5x+3=x^2+9x+15
We move all terms to the left:
2x+5x+3-(x^2+9x+15)=0
We add all the numbers together, and all the variables
7x-(x^2+9x+15)+3=0
We get rid of parentheses
-x^2+7x-9x-15+3=0
We add all the numbers together, and all the variables
-1x^2-2x-12=0
a = -1; b = -2; c = -12;
Δ = b2-4ac
Δ = -22-4·(-1)·(-12)
Δ = -44
Delta is less than zero, so there is no solution for the equation
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